5p^2+24p=5

Solution for 5p^2+24p=5 equation:

5p^2+24p=5

We move all terms to the left:

5p^2+24p-(5)=0

a = 5; b = 24; c = -5;
Δ = b2-4ac
Δ = 242-4·5·(-5)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-26}{2*5}=\frac{-50}{10}
=-5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+26}{2*5}=\frac{2}{10}
=1/5
$